Three girls X, Y and Z were asked to divide a certain number by 1547 by the method of factors. They took the factors in the order (7,13,17), (13,17,7) and (17,7,13) respectively. If the first girl X obtained (2,3,5) as successive remainder, then find the successive remainders obtained by the other two girls Y and Z.

Three girls X, Y and Z were asked to divide a certain number by 1547 by the method of factors. They took the factors in the order (7,13,17), (13,17,7) and (17,7,13) respectively. If the first girl X obtained (2,3,5) as successive remainder, then find the successive remainders obtained by the other two girls Y and Z. Correct Answer (2,1,2) and (15,5,3)

Let the number be x and corresponding quotients when divided by 1, 13 and 17 be y, z and 1 respectively. z = 17*1 + 5 = 22 y = 13*22 + 3 = 289 x = 289*7 + 2 = 2004 The successive remainders obtained by the other two girls Y and Z are (2,1,2) and (15,5,3) respectively.
Bissoy MCQ

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