A cylindrical pipe has a radius of 4 cm and length of 2 m with a thickness of 1 cm. What will be the outer curved surface area of 3 such pipes?

A cylindrical pipe has a radius of 4 cm and length of 2 m with a thickness of 1 cm. What will be the outer curved surface area of 3 such pipes? Correct Answer 1.88 m2

Given, No. = 3, r (outer) = 4 + 1 cm = 5 cm, length = 2m = 200 cm. Outer curved surface area = No. * 2πrh = 3 * 2 * (22 / 7) * 5 * 200 = 18,857 cm2 = 1.88 m2
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