Set X contains 10 consecutive integers. If the sum of the 5 smallest members of set X is 265, what is the average of the 5 largest members of Set X?

A 58
B 59
C 60
D 57

Correct Answer: 58

ধরি, প্রথম number টি a তাহলে, a + a + 1 + a + 2 + a + 3 + a + 4 = 265 বা, 5a + 10 = 265 বা, a = 265 - 105 = 51 এখন বাকি 5 টি number এর average = 15 (a + 5 + a + 6 + a + 7 + a + 8 + a + 9) = 15(51 × 5 + 35) = (51 + 7) = 58
Bissoy MCQ
#গণিত #গড় (Average) #IFIC Bank Ltd #IFIC Bank Ltd - Management Trainee Officer - 21.06.2013

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