If x+y=4 and y+z=8 and z+x=6, then 2x-y-z=?
If x+y=4 and y+z=8 and z+x=6, then 2x-y-z=? Correct Answer None of these
x + y = 4y + z = 8z + x = 6⸫ 2x + 2y + 2z = 4 + 8 + 6Now 2x + 2y + 2z - 3(y + z) = 4 + 8 + 6 - 3(y + z)2x - y - z = 4 + 8 + 6 - 3×8 [y + z = 8] = - 6