A batsman makes a score of 87 runs in the 17th ining and thus increases his average by 3. What is his average after 17th innings?
A
23
B
34
C
39
D
44
Correct Answer: 39
Let the average after 17th match is x then average before 17th match is x – 3 So, 16(x – 3) + 87 = 17x <math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>⇒</mo></math> x = 87 – 48 = 39