CH4 with pressure 10 atm and volume 5 liter at 27oC is passed into a reactor with 50% excess oxygen, how many moles of oxygen is left in the products?

CH4 with pressure 10 atm and volume 5 liter at 27oC is passed into a reactor with 50% excess oxygen, how many moles of oxygen is left in the products? Correct Answer 2

The reaction is CH4 + 2O2 -> CO2 + 2H2O, moles of CH4 = 10*5/(0.0821*300) = 2, => moles of O2 left = 2*2(50/100) = 2.
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