A beg contains 2 red, 3 green and 2 blue balls. If two balls are drawn at random, what is the probability that none of the balls drawn is blue ?
A beg contains 2 red, 3 green and 2 blue balls. If two balls are drawn at random, what is the probability that none of the balls drawn is blue ? Correct Answer 10/21
n(S) = 7C2 = 21 n( E) = 5C2 = 5! /2! 3! = 10 কোনো বলই নীল না হওয়ার সম্ভাবনা = n( E) / n(S) = 10/21