The smallest 5-digit number exactly divisible by 41 is :
The smallest 5-digit number exactly divisible by 41 is : Correct Answer 10004
Hints: The smallest 5 digit number = 10000 এটা কে 41 দ্বারা ভাগ করলে ভাগশেষ থাকে 37 এখন, Required number = 10000 + (41 - 37) = 10004