The minimum force required to slide a body of weight W on a rough horizontal plane is

A W sinϴ
B W cosϴ
C W tanϴ
D W cosecϴ

Correct Answer: W sinϴ

The minimum force required to slide a body of weight W on a rough horizontal plane is W sinϴ. A body of weight W is required to move up the rough inclined plane whose angle of inclination with the horizontal is α. The effort applied parallel to the plane is given by P = W (sinα + μ cosα).
Bissoy MCQ
#Machine Kinematics #Friction in Journal Bearing- Friction Circle

Related Questions

The minimum force required to slide a body of weight 'W' on a rough horizontal plane is
A W sinθ
B W cosθ
C W tanθ
D None of these
A body of weight 'W' is required to move up on rough inclined plane whose angle of inclination with the horizontal is 'α'. The effort applied parallel to the plane is given by (where μ = tanφ = Coefficient of friction between the plane and the body.)
A P = W tanα
B P = W tan (α + φ)
C P = W (sinα + μcosα)
D P = W (cosα + μsinα)
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The change in length due to a tensile or compressive force acting on a body is given by (where P = Tensile or compressive force acting on the body, $$l$$ = Original length of the body, A = Cross-sectional area of the body and E = Young's modulus for the material of the body)
A $$\frac{{{\text{P}}l{\text{A}}}}{{\text{E}}}$$
B $$\frac{{{\text{P}}l}}{{{\text{AE}}}}$$
C $$\frac{{\text{E}}}{{{\text{P}}l{\text{A}}}}$$
D $$\frac{{{\text{AE}}}}{{{\text{P}}l}}$$

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