A body in motion will be subjected to coriolis acceleration when that body is

A in plane rotation with variable velocity
B in plane translation with variable velocity
C in plane motion which is a resultant of plane translation and rotation
D restrained to rotate while sliding over another body

Correct Answer: restrained to rotate while sliding over another body

When a point on one link is sliding along another rotating link, such as in quick return motion mechanism, then the coriolis component of the acceleration must be calculated.
Bissoy MCQ
#Machine Kinematics #Linear Acceleration

Related Questions

The coriolis component of acceleration acts
A along the sliding surface
B perpendicular to the sliding surface
C at 450 to the sliding surface
D parallel to the sliding surface
The coriolis component of acceleration is taken into account for
A slider crank mechanism
B four bar chain mechanism
C quick return motion mechanism
D all of the mentioned
The coriolis component of acceleration depends upon
A velocity of slider
B angular velocity of the link
C all of the mentioned
D none of the mentioned
The coriolis component of acceleration leads the sliding velocity by
A 450
B 900
C 1350
D 1800
The coriolis component of acceleration exists whenever a point moves along a path that has
A linear displacement
B rotational motion
C gravitational acceleration
D tangential acceleration
The direction of Coriolis component of acceleration is the direction
A Of relative velocity vector for the two coincident points rotated by 90° in the direction of the angular velocity of the rotation of the link
B Along the centripetal acceleration
C Along tangential acceleration
D Along perpendicular to angular velocity
In a shaper mechanism, the Coriolis component of acceleration will
A Not exist
B Exist
C Depend on position of crank
D None of the above
A slider moves at a velocity $${\text{v}}$$ on a link revolving at $$\omega $$ rad/s. The coriolis component of acceleration is
A $$\omega {\text{v}}$$
B $$2\omega {\text{v}}$$
C $${\omega ^2}{\text{v}}$$
D $$2\omega {{\text{v}}^2}$$
গরম বাতাসে পরিপূর্ণ M ভরের একটি বেলুন (থ্রডি সহ) পৃথিবীর দিকে খুব ত্বরণ a তে নেমে আসছে। ঝুড়ি থেকে কি পরিমান m ভর ফেলে দিলে বেলুনটি উপরের দিকে একই খুব ত্বরন a- তে উঠে যাবে ? সকল ক্ষেত্রে বেলুনটির আয়তন একই ছিল বলে ধরে নেওয়া হলো। (g = অভিকর্ষীয় ত্বরন)(A hot air balloon with a bucket is descending towards the earth with a constant acceleration a. The combined mass of the balloon and bucket is M. What mass m from the bucket should be released so that the balloon starts ascending up with the same acceleration a? Consider the volume of the balloon remains constant at all the time. (g=acceleration due to gravity))
A m=2ag+aM
B m=g+a2M
C m=2ag M
D m=M2a(g+a)
E m=ag+M
If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion,
A P + ma = 0
B P - ma = 0
C P × ma = 0
D $$\frac{{\text{P}}}{{{\text{ma}}}} = 0$$

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