A cyclic heat engine does 50kJ of work per cycle. If efficiency of engine is 75%, the heat rejected per cycle will be ___________

A cyclic heat engine does 50kJ of work per cycle. If efficiency of engine is 75%, the heat rejected per cycle will be ___________ Correct Answer 16.6kJ

Carnot efficiency = Work done/Heat supplied(Q1) 0.75 = 50/ Q1 or, Q1 = 200/3 and, Work done = Q1– Q2 or, Q2 = 200/3-50 = 50/3 = 16.6kJ.
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