A hollow shaft outside diameter 120 mm and thickness 20 mm. Find polar moment of inertia.
A hollow shaft outside diameter 120 mm and thickness 20 mm. Find polar moment of inertia. Correct Answer 16.36 × 106 mm4
For hollow circular shaft, outside diameter = 120 mm; d = 120-2×20 = 80 mm the polar moment of inertia = π/32 × (1204– 804). J = 16.36 × 106 mm4.