A well 3 meters in diameter has its normal water level 3 meters below the ground level. By pumping water level in the well is depressed to 10 meters below the ground level. In 4 hours the water rises by 5 meters. Calculate the specific yield of the well.

A well 3 meters in diameter has its normal water level 3 meters below the ground level. By pumping water level in the well is depressed to 10 meters below the ground level. In 4 hours the water rises by 5 meters. Calculate the specific yield of the well. Correct Answer 2.213 m3/hr

Specific yield (K) is calculated from the formula, K = 2.303 (A/T) log (H1/H2) where A is the area of the well, T is the total time of recuperation to bring the water level from depth H1 to H2. Given values, A = 3.14/4 x 9 = 7.065 sq. m, T = 4 hours, H1 = 7m, H2 = 2m K = 2.303 x 7.065 x 1/4 x log (7/2) = 2.213 m3/hr under a head of one meter.

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A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that difference in the tube and well levels is hd. The angle of inclination θ of the tube with the horizontal is