Related Questions

The discharge through a rectangular channel is 16.62 m3/s and the wetted area is equal to 12m2. The width of the channel is 6m and the bed slope is 1 in 1000, calculate the value of the Chezy’s constant.
According to Chezy's formula, the discharge through an open channel is (where A = Area of flow, C = Chezy's constant, m = Hydraulic mean depth and i = Uniform slope in bed)
The ratio between normal discharge and maximum discharge through a rectangular channel is 32:6, calculate the depth of the channel if the width of the channel is 4m and bed slope, chezy’s constant remains same.
The depth and widths of a rectangular channel are 2m and 5m respectively, calculate the discharge of water through the channel if the bed slope is 1 in 500 and Chezy’s constant being 60.
The discharge of water through a trapezoidal channel is 1.5 m3/s, the base width of the channel is 7m, the depth is 2m and the side slope is 1H:3V. Bed slope is 1 in 2000, determine the value of the Chezy’s constant.
The hydraulic radius of an economical rectangular section is 4m, calculate the discharge through the channel if the bed slope of the channel is 1 in 1000 and manning’s co efficient is 0.015.
Calculate the corresponding hydraulic mean depth that would exist in the channel if the bed was unrippled. The rugosity coefficient in an unrippled channel is 0.015 and the rugosity coefficient actually observed by experiments on the rippled bed of channel is 0.020. Consider the value of hydraulic mean depth of the channel as 1.5 m.
The side slope of a triangular channel section is 1H:4V and the depth is 12m. Calculate the value of chezy’s constant if the value of manning’s constant is 0.03.
The discharge through a trapezoidal channel is 245.06m3⁄s and the bed slope is 1 in 1000. Calculate the value of the wetted area if the hydraulic radius is 2.26m. Manning’s roughness co efficient = 0.008.
Find the discharge through a circular channel section having diameter of 5m, the value of Chezy’s constant is 90 and the bed slope is 1 in 4000.