Two pipes, each of diameter d, converge to form a pipe of diameter D. What should be the relation between d and D such that the ow velocity in the third pipe becomes half of that in each of the two pipes?

Two pipes, each of diameter d, converge to form a pipe of diameter D. What should be the relation between d and D such that the ow velocity in the third pipe becomes half of that in each of the two pipes? Correct Answer D = d/2

According to the Continuity Equation, where a represents flow area, v represents flow velocity, i is for inlet conditions and o is for outlet conditions. Thus, A1v1 + A2v2 = Av d2v + d2v = Dv/2 d = D ⁄ 4.
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