A beaker of height 30 cm is partially filled with a liquid and is rotated by an angle θ as shown. At this point, the pressure at point B is found to be 5 bar. By what angle should θ be increased such that the pressure at B gets halved?

A beaker of height 30 cm is partially filled with a liquid and is rotated by an angle θ as shown. At this point, the pressure at point B is found to be 5 bar. By what angle should θ be increased such that the pressure at B gets halved? Correct Answer 15o

Let θ1 and θ2 be the angles at which the beaker is inclided for the two cases mentioned. 103 * 9.81 * 0.15 * cos θ1 = 5 * 100; θ1 = 70.12o 103 * 9.81 * 0.3 * cos θ2 = 1⁄2 * 5 * 100; θ1 = 85.12o θ2 – θ1 = 15o
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