If the average of 5 consecutive integers is 12 , what is the sum of the least and the greatest of the integers?

A 14
B 12
C 11
D 24

Correct Answer: 24

let, 5 consecutive numbers are x, (x + 1), (x + 2), (x + 3), (x + 4) = x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 12×5⇒5x + 10 = 60⇒5x = 50∴ x = 10∴x + 4 = 10 + 4 = 14∴ The of the least and the greatest of the integer 14 = 10 + 14 = 24
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