For a 4-pole, 50 Hz induction motor has starting current as 5 times to that of the full load current working at a speed of 1450rpm. The ratio of starting to full load torque will be?

For a 4-pole, 50 Hz induction motor has starting current as 5 times to that of the full load current working at a speed of 1450rpm. The ratio of starting to full load torque will be? Correct Answer 0.83

Tst/Tfl = (Ist/Ifl)^2*slip Tst/Tfl = 25*0.033 = 0.83
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