A student first reduced a number by 20 percent and then increased it again by 20 percent . If the difference between the two new numbers was 8, then what is the original number ?

A student first reduced a number by 20 percent and then increased it again by 20 percent . If the difference between the two new numbers was 8, then what is the original number ? Correct Answer 50

Suppose, Total marks = 10020% reduced = 80Then, 20% increased = 80 + 80 of 20% = 96Difference = 100 - 96 = 44 difference then orginal number = 1008 difference then orginal number = (100×8)/4                                                = 20020% increased = 96% Difference between two new number=  96-80 = 16Difference is 16 when the original number is 100   ,,            ,,   8   ,,      ,,   = 50Answer : 50
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