The sum of 6 consecutive odd numbers exceeds twice the largest by 38. Find the sum of the six numbers ?

The sum of 6 consecutive odd numbers exceeds twice the largest by 38. Find the sum of the six numbers ? Correct Answer 72

Let x represent the smallest number. Then the other number are x + 2, x + 4, x + 6, x + 8 and x + 10. x + 10 is the largest. The sum of these is 6x + (2 + 4 + 6 + 8 + 10) = 6x + 30 We are told that this is 38 greater than twice the largest, so 6x + 30 = 2(x + 10) + 38 = 2x + 58. or, 4x = 28 ∴x = 7 Then the sum is 6×7 + 30 = 72. 
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