What is the discrete-time signal obtained after sampling the analog signal x(t)=cos(2000*pi*t)+sin(5000*pi*t) at a sampling rate of 5000 samples/sec?

What is the discrete-time signal obtained after sampling the analog signal x(t)=cos(2000*pi*t)+sin(5000*pi*t) at a sampling rate of 5000 samples/sec? Correct Answer cos(0.4*pi*n)+sin(pi*n)

From the given analog signal, F1=1000Hz F2=2500Hz and Fs=5000Hz =>f1=F1/Fs and f2=F2/Fs =>f1=0.2 and f2=0.5 =>x(n)=cos(0.4*pi*n)+sin(pi*n).
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