A cricketer has a certain average for 9 innings. In the 10th innings he scores 100 runs, thus increasing his average by 8 runs. His new average is :

A cricketer has a certain average for 9 innings. In the 10th innings he scores 100 runs, thus increasing his average by 8 runs. His new average is : Correct Answer 28

Let, initial average = x So, total runs = 9x And total runs scored in 10 innings = 9x + 100 So, new average = (9x + 100)/10 Since average increase by 8 ATQ, x + 8 = (9x + 100)/10 10x + 80 = 9x + 100 x = 20 New average 20 + 8 = 28 (Ans)
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