Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. what is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. what is the probability that the ticket drawn has a number which is a multiple of 3 or 5? Correct Answer 9/20

S = [1,2,3,4, - - - - - - 19,20] ধরি, E = event of 3 অথবা 5 এর multiple পাবার সম্ভাব্যতা = [3,6,9,12,15,18,5,10,20] ⸫ P(E) = n(E)/n(S) = 9/20
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