For the device shown here, assume the D input is LOW, both S inputs are LOW and the input is LOW. What is the status of the Y’ outputs?

For the device shown here, assume the D input is LOW, both S inputs are LOW and the input is LOW. What is the status of the Y’ outputs? Correct Answer All but Y0 are HIGH

In the given diagram, S0 and S1 are selection bits. So, I/P S0 S1 O/P D = 0 0 0 Y0 D = 0 0 1 Y1 D = 0 1 0 Y2 D = 0 1 1 Y3 Hence, inputs are S0 and S1 are Low means 0, so output is Y0 and rest all are HIGH.
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A perceptron adds up all the weighted inputs it receives, and if it exceeds a certain value, it outputs a 1, otherwise it just outputs a 0.