If y(x) = tan-1x then

If y(x) = tan-1x then Correct Answer (yn+1)(0) = -n(n-1)(yn-1)0

Y = tan-1x Y1 = 1/(1+x2) (1+x2)y1 = 1 By Leibniz Rule, (1+x2)yn+1 + 2nxyn + n(n-1)yn-1 = 0 Put x=0, gives → (yn+1)(0) = -n(n-1)(yn-1)(0).
Bissoy MCQ

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