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A lexical analyzer uses the following patterns to recognize three tokens T1, T2, and T3 over the alphabet {a,b,c}. ?1: ?? (?|?)∗? ?2: ?? (?|?)∗? ?3: ?? (?|?)∗? Note that ‘x?’ means 0 or 1 occurrence of the symbol x. Note also that the analyzer outputs the token that matches the longest possible prefix. If the string ???????? is processed by the analyzer, which one of the following is the sequence of tokens it outputs?
What is the output of lexical analyzer?
The lexical analyzer takes _________ as input and produces a stream of _______ as output.
The output of the lexical and syntax analyzer can stated as:
Lexical Analysis Identifies Different Lexical Units in a _______
State true or false: Statement: A lexical analyzer reads the source code line by line.
Which among the following is not a tool to construct lexical analyzer from a regular expression?
Wages of the workers are normally, the proportionality derived from their efficiency. But the concept of efficiency of labour is itself vague such as amount of physical output, output per man hour or output per man shift. But output is not the function of man alone. There are other factors which affect the output. Which among the following is/are not the factor(s) that would affect the output directly?
1. Physical condition of work
2. Nature of machinery
3. Technical process
4. Quality of raw material
5. System of management
6. Role of fellow workers
7. Competitors in the market
A system provides output yi(t) when xi(t) is applied. If the system is said to be LTI then which of the following properties must satisfy? (i).If the input is x3 = ax1(t) + bx2(t), then output must be y3(t) = ay1(t) + by2(t) (ii).If the input is x(t – T), then the output must be y (t – T) (iii).If the input is x3 = ax1(t) + bx2(t), then output must be y3(t) = ay1(t) * by2(t) (iv).If the input is x(t – T), then the output must be y(t + T)
What is the output after compile and run the following code ? int Output = 10;
boolean b = false;
if((b == true) && ((Output += 10) == 20))
{
System.out.println("We are equal " + Output);
}
else
{
System.out.println("Not equal! " + Output);
}