If the cooperative (from the previous question) has the greatest number of members possible (with a minimum of Tk. 240 contribution) and all members except one paid exactly Tk. 240, then how much did the member who paid higher than the rest, pay?

A Tk. 200
B Tk. 680
C Tk. 440
D Tk. 280

Correct Answer: Tk. 440

Greatest number of members possible = 5000 / 240 ≈ 20. Let the payment made by the single member be X. The rest 19 members paid TK. 240 each. So,  240×19 + X = 5000 or,  X = 5000 - 4560 = 440 TK
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