how many 3digit numbers can be formed from digits 2,3,5,6,7 and 9 divisible by 5 and none of the digits is repeated?

how many 3digit numbers can be formed from digits 2,3,5,6,7 and 9 divisible by 5 and none of the digits is repeated? Correct Answer 5

Numbers divisible by 5 must have the digit 5 in their unit place. As no numbers can be repeated, there are only 2 numbers remaining to be chosen from 5 more numbers (2, 3, 6, 7, 9). So, number of possible numbers =  5P2  = 20

Related Questions