how many 3digit numbers can be formed from digits 2,3,5,6,7 and 9 divisible by 5 and none of the digits is repeated?
how many 3digit numbers can be formed from digits 2,3,5,6,7 and 9 divisible by 5 and none of the digits is repeated? Correct Answer 5
Numbers divisible by 5 must have the digit 5 in their unit place. As no numbers can be repeated, there are only 2 numbers remaining to be chosen from 5 more numbers (2, 3, 6, 7, 9). So, number of possible numbers = 5P2 = 20
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Feb 20, 2025