If ab-2cd = p; 6cd-3ab=1; what is the value of p?
If ab-2cd = p; 6cd-3ab=1; what is the value of p? Correct Answer -1/3
Given That , 6cd - 3ab = 1 ⇒ 3(2cd - ab) = 1 ⇒ 2cd - ab = 13 another equation is, ab - 2cd = p ⇒ -1(2cd - ab)= p ⇒ -13 = p (putting the value of 2cd - ab) Ans: P = -13