If ab-2cd = p; 6cd-3ab=1; what is the value of p?

If ab-2cd = p; 6cd-3ab=1; what is the value of p? Correct Answer -1/3

Given That ,             6cd - 3ab = 1       ⇒ 3(2cd - ab) = 1       ⇒ 2cd - ab = 13   another equation is,          ab - 2cd = p      ⇒ -1(2cd - ab)= p     ⇒ -13 = p               (putting the value of 2cd - ab) Ans: P = -13               
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