If ab-2cd = p; 6cd-3ab=1; what is the value of p?

A -3
B -1/3
C 1/3
D 3

Correct Answer: -1/3

Given That ,             6cd - 3ab = 1       ⇒ 3(2cd - ab) = 1       ⇒ 2cd - ab = 13   another equation is,          ab - 2cd = p      ⇒ -1(2cd - ab)= p     ⇒ -13 = p               (putting the value of 2cd - ab) Ans: P = -13               
Bissoy MCQ
#গণিত #সাধারণ সূত্রাবলী (General formulas) #Mercantile Bank Ltd #Mercantile Bank Ltd - Officer - 2006

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