Bissoy.com
Doctors Medicines MCQs Q&A

Today Jim is twice as old as Fred and Sam is 2 years younger than Fred. Four years ago Jim was 4 times as Sam. How old is Jim now?

Today Jim is twice as old as Fred and Sam is 2 years younger than Fred. Four years ago Jim was 4 times as Sam. How old is Jim now? Correct Answer 20

let J, S, and F = the current age of Jim, Fred, and Sam, respectively and create the equations:J = 2FAndS = F - 2S + 2 = FAndJ - 4 = 4(S - 4)J - 4 = 4S - 16J = 4S - 12Since J = 2F we have:2F = 4S - 12F = 2S - 6Since S + 2 = F, we have:S + 2 = 2S - 68 = S, so J = 4 x 8 - 12 = 20.Answer: 20

Related Questions

Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ?
Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$
Each question below is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer. 11 Aman is how many years younger than Jadhav? I. Six years back Lokesh was as old as Aman is now. The ratio of age of Lokesh three ago and age of Jadhav 2 years ago was 7 ∶ 11. II. Jadhav is 3 years younger than Ranjit. The ratio of the age of Lokesh 2 years ago and the present age of Ranjit is 3 ∶ 5.
Five friends - David, Ethan, Fred, Gilbert, and Harry were sitting around a circular table facing the center of the table. Harry was sitting next to neither David nor Fred. Gilbert is sitting to the immediate left of Fred. Who among the following is sitting to Fred's immediate right?
Given below are two quantities named 1 and 2. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers. Quantity 1: How many years ago were Brad and Angelina married? The ratio of the age of Brad and Angelina is 4 : 3. At the time of marriage the ratio was 5 : 3 and After 4 years this ratio will become 9 : 7. Quantity 2: The present age of the younger son. The younger son is 3 years younger than the elder one. 10 years ago, the father was twice of his elder son and the difference of their present ages is 15 years.
$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$            is equal to = ?
Given below are quantities named A,B and C. Based on the given information, you have to determine the relation between the quantities. You should use the given data and your knowledge of mathematics to choose among the possible answer. Akash’s present age is six years less than Badshah’s age after nine years. The ratio of present age of Badshahand RAFTAAR is 5:9. Raftaar is 21 years younger than Denny and Denny is three years older than Honey. Square of the Honey’s present age is 1350 more than 15 times of Honey’s present age? Quantity A: What is the difference between AKASH’s present age and HONEY’s age after 16 years? Quantity B: After 6 years Mankirat’s age is twice that of Akash’s present age. Diljeet’s present age is 3.5 times of 25% of sum of present age of Mankirat and A. What is the present age of Diljeet? Quantity C: Twice of A’s present age is eight years more than that of Babbu’spresent age, then find the Babbu’s present age?
Today jishan is twice as old as Farid and Samsu is 2 younger than Farid four years ago Jishan was 4 times as old as Samu. How old is Jishan now?
Ram and Sam are two employees of a company. Salary of Ram is 37.5% of the total salary of Ram and Sam. Sam saves 60% of his salary and total savings of Ram and Sam is 50% of their total income. If their average expenditure is Rs. 16000, what is the salary of Sam?
Questions below followed by three quantities. Find the relationship between them. Quantity I: Average age of 14 members of team is 25 years. While oldest member of the team is 26 years older than youngest member of the team. Out of remaining 12 members of team, average age of six members of team is 28 years and the remaining six members is 20 years. What is the age of oldest member of the team? Quantity II: Average age of Nitu, Rekha and Shyam is 17 years. Two new persons Divya and Raju joined them so that average age of all become 19 years. If Divya is 2 years older than Raju and Rekha is 2 years older and 1 year older than Shyam and Nitu respectively. What is sum of the average age of Nitu and Shyam together and average age of Divya and Rekha together? Quantity III: The average age of father, mother and their two sons is 27.5. Five years ago, the ratio of ages of father, mother and two sons (elder and younger) is 7 : 5 : 2 : 1. Find the sum of ages of two sons after 7 years.