In the powder method of the crystals if the Bragg’s angle is Θ then what is the angle of the cone formed by the diffracted beams?

In the powder method of the crystals if the Bragg’s angle is Θ then what is the angle of the cone formed by the diffracted beams? Correct Answer 4Θ

The diffracted beams in the powder method forms a cone, if the Bragg’s angle is Θ, then the angle between diffracted and undiffracted beams is 2Θ and the angle of the cone is 4Θ. Each set of planes gives its own cone of radiation.
Bissoy MCQ

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