If the magnetic meridian of a certain place, the horizontal component of the earth’s magnetic field is 0.26 G and the dip angle is 60°, what is the magnetic field of earth at this location?
If the magnetic meridian of a certain place, the horizontal component of the earth’s magnetic field is 0.26 G and the dip angle is 60°, what is the magnetic field of earth at this location? Correct Answer 0.52 G
It is given that, HE = 0.26 G. Thus, we have cos60° = HE/BE BE = HE/ cos60° = 0.26 X 2 = 0.52 G.