Two simple pendulum, whose lengths are 100cm and 121cm, are suspended side by side. Their bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum, will the two be in phase again?

Two simple pendulum, whose lengths are 100cm and 121cm, are suspended side by side. Their bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum, will the two be in phase again? Correct Answer 10

T∝√l For the two pendulums in same phase nT1=(n+1) T2 n√(l1)=(n+1) √(l2) n√121=(n+1)√100 n×11=(n+1)10 n=10.
Bissoy MCQ

Related Questions

If the amplitude or oscillation of a simple pendulum is very small, then its time period of oscillation
1. depends on the length of the pendulum, L.
2. depends on the acceleration due to gravity, g.
3. depends upon the mass of the bob of the pendulum, m.
4. does not depend upon the amplitude of the pendulum, A.
Select the correct answer:
A pendulum clock is lifted to a height where the gravitational acceleration has a certain value of g. Another pendulum clock of same length, but of double the mass of the bob is lifted to another height where the gravitational acceleration is $$\frac{g}{2}$$. The time period of the second pendulum would be (in terms of period T of the first pendulum)
A simple pendulum has a time period T. The pendulum is completely immersed in a non-viscous liquid, whose density is 1/10th of that of the material of the bob. The time period of the pendulum is immersed in the liquid is?
A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the increase in the time period of the pendulum of increased length is?
The time period of a simple pendulum made by using a thin copper wire of length L is T. Suppose the temperature of the room in which this simple pendulum is placed increases by 30°C. What will be the effect on the time period of the pendulum?
Two simple pendulums of lengths 5m and 20m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed.
Which is the longer: P is equal to Q, R is shorter than P, S is longer than R. T is longer than Q, is longer then S.
There is a simple pendulum hanging from the ceiling of a lift. When the lift is standstill, the time period of the pendulum is T. If the resultant acceleration becomes g/4, then the new time period of the pendulum is?
Which of the following statements are true/false?
1. In case an employee whose minimum rate of wages is fixed under this Act, works overtime, the employer need not pay the money for the extra hours devoted by the employee.
2. If an employee whose minimum rate of wages has been fixed under this Act, works for a less number of hours than the requisite number of hours on a given day, he shall be entitled to receive wages in respect ofwork done by him on that day as ifhe had worked for a full normal working day.
3. In case an employee is involved in two or more classes of work, he shall be paid on the basis of pieces involved.
4. If an employee is employed on piece work for which minimum time rate and not a minimum piece rate has been fixed under this Act, the employer shall pay to such employee wages at not less than the minimum time rate.
The time period of a simple pendulum depends on
(i) Mass of suspended particle
(ii) Length of the pendulum
(iii) Acceleration due to gravity