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A stone tied to the end of string 80cm long is whirled in horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 sec, what is the magnitude of acceleration of the stone?

A stone tied to the end of string 80cm long is whirled in horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 sec, what is the magnitude of acceleration of the stone? Correct Answer 990 cm/s2

a = rω2 = r(2πn/t)2 a = (80×4×(22/7)2×142)/142 = 990cm/s2.

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