Boiling point of chloroform is 61°C. After addition of 5.0 g of a non-volatile solute to 20 g chloroform boils at 64.63°C. If kb = 3.63 K kg mol-1, what is the molecular weight of the solute?

Boiling point of chloroform is 61°C. After addition of 5.0 g of a non-volatile solute to 20 g chloroform boils at 64.63°C. If kb = 3.63 K kg mol-1, what is the molecular weight of the solute? Correct Answer 250 g/mol

Given, b.p. of chloroform = 61°C New b.p. after addition = 64.63°C Mass of solute, w2 = 5.0 g Mass of solvent, w1 = 20 g Kb = 3.63 K kg mol-1 From these, ∆Tb = 64.63 – 61 = 3.63°C Using ΔTb = (kb x 1000 x w2)/(M2 x w1) M2 = (kb x 1000 x w2)/(ΔTb x w1) M2 = (3.63 x 1000 x 5)/(3.63 x 20) = 250 g/mol.
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