What is the number of moles in 650 mL of 98% (v/v) sulfuric acid solution if density of sulfuric acid is 1.83 g/cm3?

What is the number of moles in 650 mL of 98% (v/v) sulfuric acid solution if density of sulfuric acid is 1.83 g/cm3? Correct Answer 11.9

98% (v/v) means 98 mL of acid is present in 100 mL of solution. In 650 mL of solution, volume of acid present = 0.98 x 650 mL = 637 mL Mass of acid present = volume x density = 637 mL x 1.83 g/mL =1165.71 g Molar mass of sulfuric acid (H2SO4) = (2 x 1 + 32 + 4 x 16) = 98 g/mole Number of moles of sulfuric acid = mass/molar mass = 1165.71g/(98 g/mole) = 11.9 moles.
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