The velocities of three particles of masses 10 kg, 20 kg and 30 kg are 10i, 10j and 10k m/s, respectively. What is the velocity of their centre of mass?

The velocities of three particles of masses 10 kg, 20 kg and 30 kg are 10i, 10j and 10k m/s, respectively. What is the velocity of their centre of mass? Correct Answer (i + 2j + 3k) m/s

The velocity of the centre of mass = (m1*v1 + m2*v2 + m3*v3)/(m1 + m2 + m3) = (10*10i + 20*10j + 30*10k) / (10 + 20 + 30) = (100i + 200j + 300k) / 100 = (i + 2j + 3k) m/s.
Bissoy MCQ

Related Questions

The masses of two balls are in the ratio of 2 : 1 and their respective velocities are in the ratio of 1 : 2 but in opposite direction before impact. If the coefficient of restitution is $$\frac{1}{2}$$, the velocities of separation of the balls will be equal to