A body moves from point A (3,6) to point B (11,12) to point C (15,15). What is the average speed of the body along the given path if the total time taken is 100s?

A body moves from point A (3,6) to point B (11,12) to point C (15,15). What is the average speed of the body along the given path if the total time taken is 100s? Correct Answer 0.15 units/s

The distance between A and B is 10 units. The distance between B and C is 5 units. Hence, the total distance is 15 units. The total time taken is 100 s. Average speed = total distance/total time taken = 15/100 = 0.15 units/s.
Bissoy MCQ

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৫ঃ১৮ঃ,৭ঃ২ এবং ৩ঃ৬ এর মিশ্র অনুপাত কত?
৫ঃ১৮, ৭ঃ২ এবং ৩ঃ৬-এর মিশ্র অনুপাত কত ?