A ball is thrown up with an initial velocity of 20 m/s and after some time it returns. What is the maximum height reached? Take g = 10 m/s2.

A ball is thrown up with an initial velocity of 20 m/s and after some time it returns. What is the maximum height reached? Take g = 10 m/s2. Correct Answer 20m

Here we will use the third equation of motion. The third equation of motion is v2 = u2 + 2as. At the maximum height, the velocity of the ball will be zero, therefore, v = 0, u = 20, and a = -g = -10. On solving, we will get s = 20m.
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