Evaluate tan2 A + (1 + sec A) (sec A – 1).
Evaluate tan2 A + (1 + sec A) (sec A – 1). Correct Answer 2tan2 A
tan2 A + (1 + sec A) (sec A – 1) = tan2 A + (sec A + 1) (sec A – 1) = tan2 A + (sec2 A – 1) = tan2 A + tan2 A = 2tan2 AEvaluate tan2 A + (1 + sec A) (sec A – 1). Correct Answer 2tan2 A
tan2 A + (1 + sec A) (sec A – 1) = tan2 A + (sec A + 1) (sec A – 1) = tan2 A + (sec2 A – 1) = tan2 A + tan2 A = 2tan2 A