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dydx  নির্ণয় কর, tan y = 2t1-t2, sin x =2t1+t2

dydx  নির্ণয় কর, tan y = 2t1-t2, sin x =2t1+t2 Correct Answer dydx =1

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y=tan (sin-1x) = হলে y=tan (sin-1x) হলে dydx নির্ণয় কর।
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\[{\text{f}}\left( \theta \right) = \left| {\begin{array}{*{20}{c}} {\sin \theta }&{\cos \theta }&{\tan \theta } \\ {\sin \left( {\frac{\pi }{6}} \right)}&{\cos \left( {\frac{\pi }{6}} \right)}&{\tan \left( {\frac{\pi }{6}} \right)} \\ {\sin \left( {\frac{\pi }{3}} \right)}&{\cos \left( {\frac{\pi }{3}} \right)}&{\tan \left( {\frac{\pi }{3}} \right)} \end{array}} \right|\