Related Questions

' If we cooperate together by dividing up the work : we shall be able to finish it quickly.
A If we cooperate together by dividing up the work
B If we cooperate by dividing up
C If we cooperate together by dividing the work
D If we cooperate by dividing up the work togehter
Four men and 6 women finish a job in 8 days. while 3 men and 7 women finish it in 10 days. while 3 men and 7 women finish it in 10 days. In how many days will 10 women take to finish the work together?
A 32
B 36
C 40
D None
If we finish our work quickly, we can go to the movies. Here QUICKLY is a/an-
A Adverb
B Conjunction
C Verb
D Adjective
Rumi and Rony can finish a task, working together, in 12 days. If Rony alone can finish that in 20 days, how many days will Rumi need to finish the task working alone ?
A 30
B 20
C 25
D 33
"To Look quickly through a book is an important study skill." What is the meaning of the "To look quickly through" phrase in the sentence?
A Skim
B Outline
C Summarize
D Paraphrase
The man said, "What I give today I trust that tomorrow I shall be able to earn back."
A The man said that what he gave that day he trusted he would be able to return the next day.
B The man said to give him his trust so that he would be able to earn back the next day.
C The man asked what to give that day as he trusted that the next day he would earn back.
D The man said that he trusted he would be able to earn back the next day what he gave that day.
A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work they can finish in a day ?
A 2/5
B 1/6
C 1/9
D 2/7
30 labourers, working 7 hours a day can finish a piece of work in 18 days. If the ladourers work 6 hours a day, then the number of labourers to finish the same piece of work in 30 days, will be.
A 15
B 22
C 21
D 25
If D is the duration, ES and EF are the earliest start and finish, LS and LF are latest start and latest finish time, then the following relation holds good
A EF = ES + D
B LS = LF - D
C LF = LS + D
D All the above
If E is the duration, ES and EF are die earliest start and finish times, LS and LF are latest start and finish times, then the following relation holds good
A EF = ES + D
B LS = LFD
C LF = LS + D
D All of the above

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