The sum of three consecutive number is 123, The product of two smaller number is :

A 625
B 900
C 1600
D 1680

Correct Answer: 625

Let,   the three numbers are x, x+1, x+2   Here, two smaller numbers are x, x+1 respectively   The sum of three consecutive number is     3X+3 = 123                                                                                so, X= (123-3)/3                                                                                    = 40Two smallers numbers are 40 and 41 respectivelySo their product is 40*41 = 1640Answere: 1640
Bissoy MCQ
#গণিত #Bangladesh Bank #দ্বিঘাত সমীকরণ (Quadratic equation) #Bangladesh Bank - Assistant Director - 2004

Related Questions

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cos-123-cos-16+123 এর মান কত?
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