The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is –

Cannot be determined

The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is – Correct Answer 20

a2 + b2 + c2 = 138ab + ac + bc = 131a + b + c = ? Now, we know,(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc=> (a + b + c)2 = 138 + 2×131 => (a + b + c)2 = 400 => a + b + c = √400 => a + b + c = 20Ans. 20