Related Questions

The perimeters of two squares are 40cm and 30cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.
A 18cm
B 24cm
C 32cm
D 36cm
If the ratio of the areas of 2 squares is 2:1 , then the ratio of the perimeters of the squares is
A 1 : 2
B 2 : 1
The length of each side of square A is increased by 100 percent to make square B. Again the length of each side of square B is increased by 50 percent to make square C. By what percent is the area of square C greater than the sum of the areas of square A and B?
A 75%
B 80%
C 85%
D 90%
A small square region inside a larger square is shaded. The diagonal of the larger square is three times the diagonal of the small square in length. What fraction of the area of the larger square is not shaded?
A 1/9
B 1/3
C 2/3
D 8/9
The length of each of square A is increased by 100 percent to make square B.Again the length of the each side of square B is increased by 50 peacent to make square C.By of the area df square A and B?
A 75%
B 80%
C 85%
D 90%
The length of rectangle ABCD is 6/5th of its breadth, its perimeters 132 . Find its area.
A 660 m2
B 2210m2
C 1080 m2
D 2160 m2
Shahin has purchased a square sheet of plywood of 169 square feet area. To cover a wall he must cut off two feet from a side. What is the area, in square feet, of the wall?
A 117
B 121
C 143
D 141
Lubana has purchased a square sheet of plywood of 289 square feet area. To cover a wall she must cut of two feet from side what is the area,in square feet of the wall?
A 225
B 230
C 235
D 240
How many squares will there be, if a rectangle of area 60 is cut into squares of side 1/2?
A 30
B 60
C 120
D 180
Two circular dials of exactly the same size are mounted on a wall side by side in such a way that their perimeters touch at one point. Dial 1, which is on the left , spins clockwise around its center , and dial 2 , which is on the right spins counter clockwise around its center . (Assume that there is no friction at the point of contact between the dials.) Each dial is marked on its perimeter at three points that are at equale distances around the points arked ondial 1 are N, O, and P and the points marked on dial 2 are X, Y, and Z. If points O and Z are just meeting at the point of contact between the dials , and if dial 1 spins at the same speed as dial 2, what is the smallest number of revolutions of each dial that will bring O and Z together again?
A 1
B 2
C 3
D 4

Next steps