A father's age is four times his son's age now. Twenty years from now, the father's age will be double his son's age. What will be the son's age ten years from now?

A 10
B 15
C 20
D 30

Correct Answer: 20

Let say Son's Present Age x             Father Present Age 4x20years later , Son = x+20                          Father = 4x + 20    20 years later F = 2 S,                 4x+ 20 = 2(x+20)                 4x+20 = 2x + 40                   x = 10Son Present Age = 1010 years later Son Will be = 10+10 =20 Years                
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