P is now 8 years older than Q. 17 years ago P was twice as old as Q. How old will Q be in 10 years ?

P is now 8 years older than Q. 17 years ago P was twice as old as Q. How old will Q be in 10 years ? Correct Answer 35

Let, the present age of P is X and Q is Y.X = Y+8    ……………..(i)X-17 = 2(Y-17)   ………….(ii)Evaluating eqn(ii) we get,X-17 = 2Y-34→X = 2Y-17  ……………..(iii)By subtracting eqn(i) from eqn(iii) we get,0 = Y-25→Y = 25So, the present age of Q is 25.After 10 years Q will be = 25+10= 35. 
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