In a box , there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green ?
A
1/3
B
3/4
C
7/19
D
8/21
Correct Answer: 1/3
Probability = Favorable outcome/ Total No. of outcome R - 8 , B - 7 , G - 6 Total, = 8 + 7 + 6 = 21 P(B) = 7/21 = 1/3