যদি কোন দ্রবণের OH-=3.4×10-5Mহয়, তবে দ্রবনটির ph কত?

A 4.47
B 7.44
C 9.53
D 5.93

Correct Answer: 9.53

 [OH-]  = 3.4×10-5MPOH = -log[OH-] = -log(3.4×10-5) = 4.48pH = 14 - POH = 14 - 4.49 = 9.52 
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